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An alternating voltage given as V = 200√2 sin(100t) V is applied to a capacitor of 1 μF. The current reading of the ammeter will be equal to ______ mA.

Asked in RS Academy GUJCET booklet · Reactance and frequency

• (1) 100
• (2) 20
• (3) 40
• (4) 80

Step-by-step solution

Why the other options are wrong

• (1) No single slip gives 100 mA from these values; it is the reading for a 5 μF capacitor. Sanity check: 200×100×1×10⁻⁶ = 0.02 A.
• (3) No single slip gives 40 mA; it is the reading for 2 μF. Sanity check: X_C = 1/(100×10⁻⁶) = 10⁴ Ω and (200 V)/(10⁴ Ω) = 0.02 A.
• (4) No single slip gives 80 mA; it is the reading for 4 μF, four times this capacitance.

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