Practice portal › Alternating Current › Resonance in Series LCR
Asked in RS Academy GUJCET booklet · Resonance condition and tuning
Idea: at resonance the inductive and capacitive reactances are equal, X_L=X_C.
ω₀L=1/(ω₀C)⇒ω₀²=1/(LC)⇒ω₀=1/(√LC).
With ω₀=2π f₀: f₀=1/(2π√LC).
R does not appear: it decides how sharp the resonance is, not where it occurs.
So f₀=1/(2π√LC).
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