Practice portal › Alternating Current › Resonance in Series LCR
Asked in GUJCET 2009 · Current and voltage at resonance
Given: V_R=5 V, V_L=10 V, V_C=10 V (rms values).
Idea: in a series circuit V_L leads the current by 90° and V_C lags it by 90°, so they point in opposite directions on the phasor diagram.
V=√V_R²+(V_L-V_C)²=√5²+(10-10)²=5 V.
At resonance the inductor and capacitor voltages cancel, and the whole supply voltage appears across R.
So the applied voltage is 5 V.
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