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When does the impedance of a series L–C–R (AC) circuit become minimum?

Asked in RS Academy GUJCET booklet · Resonance condition and tuning

Answer: (4) when the imaginary part of the impedance is equal to zero

Step-by-step solution

Impedance of a series LCR circuit: Z=√R²+(X_L-X_C)².

In complex form Z=R+j(X_L-X_C): R is the real part and X_L-X_C the imaginary part.

R is fixed, so Z is least when (X_L-X_C)² is zero.

That happens when X_L=X_C, which is resonance, and then Z=R.

So the impedance is minimum when its imaginary part is zero.

Why the other options are wrong

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