Practice portal › Alternating Current › Resonance in Series LCR

For an LCR series circuit, L = 2.0 H, C = 32 μF and R = 10 Ω. ______ is the Q value for this circuit.

Asked in GSEB Board August 2020 · Power and bandwidth at resonance

• (1) 395
• (2) 279
• (3) 40
• (4) 25

Step-by-step solution

Why the other options are wrong

• (1) No single slip gives 395. Sanity check: √L/C = √(2.0)/(32×10⁻⁶) = 250 Ω, and dividing by R = 10 Ω gives 25.
• (2) No single slip gives 279. Sanity check: ω₀ = 1/(√LC) = 125 rad s⁻¹, and Q = (ω₀L)/R = (125×2.0)/(10) = 25.
• (3) No single slip gives 40; it would need R = (250)/(40) = 6.25 Ω, but the circuit has 10 Ω.

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