Practice portal › Alternating Current › Series LCR: Impedance and Phase
Asked in GSEB Board March 2018 · Impedance and phase angle
Given: f = (50)/π Hz, R = 100 Ω, L = 1 H.
Inductive reactance: X_L = 2π fL = 2π×(50)/π×1 = 100 Ω.
Idea: in an L-R circuit the voltage leads the current by φ, where tan φ = (X_L)/R.
tan φ = (100)/(100) = 1, so φ = 45°.
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