Practice portal › Alternating Current › Power in AC Circuits
Asked in GSEB Board July 2015 · Power factor
Given: a series L-C-R circuit driven at its resonant frequency.
Idea: at resonance X_L=X_C, so the net reactance X_L-X_C is zero.
Then Z=√R²+(X_L-X_C)²=R and tan δ=(X_L-X_C)/R=0, so δ=0.
Power factor cos δ=R/Z=1: voltage and current are in phase and the circuit takes the most power it can.
So the power factor is 1.
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