Practice portal › Alternating Current › Power in AC Circuits
Asked in GSEB Board July 2016 · Average power and heating
Given: V₀=100 V, I₀=100 mA=0.1 A, phase difference φ=π/3=60°.
Idea: average power P=VᵣₘₛIᵣₘₛ cos φ=(V₀I₀)/2 cos φ.
(V₀I₀)/2=(100×0.1)/2=5 W.
cos 60°=1/2, so P=5×1/2=2.5 W.
So the power in the circuit is 2.5 W.
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