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For a series LCR circuit with L=2 H, C=18 μF and R=10 Ω, what is the value of the Q-factor of this circuit?

Asked in GUJCET 2021 · Power and bandwidth at resonance

Answer: (4) 33.33

Step-by-step solution

Given: L=2 H, C=18 μF=18×10⁻⁶ F and R=10 Ω.

Idea: Q=(ω₀L)/R with ω₀=1/(√LC), which simplifies to Q=1/R√L/C.

L/C=2/(18×10⁻⁶)=(10⁶)/9, so √L/C=(1000)/3=333.3 Ω.

Q=(333.3)/(10)=33.33.

So the Q-factor is 33.33.

Why the other options are wrong

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