Practice portal › Alternating Current › Resonance in Series LCR
Asked in GUJCET 2021 · Power and bandwidth at resonance
Given: L=2 H, C=18 μF=18×10⁻⁶ F and R=10 Ω.
Idea: Q=(ω₀L)/R with ω₀=1/(√LC), which simplifies to Q=1/R√L/C.
L/C=2/(18×10⁻⁶)=(10⁶)/9, so √L/C=(1000)/3=333.3 Ω.
Q=(333.3)/(10)=33.33.
So the Q-factor is 33.33.
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