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Wave has simple harmonic motion whose period is 4 seconds while another wave which also possesses simple harmonic motion has its period 3 second. If both are combined, then the resultant wave will have the period equal to

Asked in NEET 1993 · Beat frequency

Answer: (3) 12 s

Step-by-step solution

Given: two simple harmonic motions of periods 4 s and 3 s.

Idea: superposing two frequencies produces beats, whose frequency is the difference of the two.

u₁=1/4 Hz and u₂=1/3 Hz.

u_beat=1/3-1/4=(4-3)/(12)=1/(12) Hz.

T_beat=1/(u_beat).

T=12 s.

Why the other options are wrong

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