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Standing waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave velocity is 20 m/s, the frequency is

Asked in NEET 1997 · Nodes, antinodes and harmonics

Answer: (1) 5 Hz

Step-by-step solution

Given: ℓ=10 m, 5 segments, v=20 m/s.

Idea: each segment of a standing wave on a string is half a wavelength long.

5×λ/2=10 m, so λ=4 m.

f=v/λ=(20)/4.

f=5 Hz.

(Equivalently f=(n v)/(2ℓ)=(5×20)/(20).)

Why the other options are wrong

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