Two waves having equation x₁=a sin(ω t-kx+φ₁) and x₂=a sin(ω t-kx+φ₂). If in the resultant wave the frequency and amplitude remain equal to amplitude of superimposing waves, the phase difference between them is

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(2) (2π)/3. Given: two waves of equal amplitude a and the same frequency, differing in phase by φ; the resultant amplitude is also a. Idea: two equal amplitudes at a phase difference φ add to 2a cos φ/2. 2a cos φ/2=a. cos φ/2=1/2. φ/2=π/3. φ=(2π)/3.

Two waves having equation x₁=a sin(ω t-kx+φ₁) and x₂=a sin(ω t-kx+φ₂). If in the resultant wave the frequency and amplitude remain equal to amplitude of superimposing waves, the phase difference between them is

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Why the other options are wrong