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Asked in NEET 2002 · Source moving at an angle
Given: ω=20 rad/s, r=50 cm =0.5 m, f=385 Hz, v=340 m/s.
Idea: the pitch is lowest at the instant the whistle is moving directly away from the distant observer, at its full speed.
vₛ=rω=0.5×20=10 m/s.
Receding source: f'=f(v/(v+vₛ)).
f'=385×(340)/(350).
f'=374 Hz.
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