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Asked in NEET 2012 Mains · Particle velocity and wave velocity
Given: y=3 sin π/2(50t-x).
Expanding, y=3 sin (25π t-π/2x), so A=3, ω=25π, k=π/2.
Wave velocity: v=ω/k=(25π)/(π/2)=50 m s⁻¹.
Maximum particle velocity: (vₚ)ₘₐₓ=Aω=3×25π=75π m s⁻¹.
((vₚ)ₘₐₓ)/v=(Aω)/(ω/k)=Ak.
Ak=3×π/2=3/2π.
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