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Asked in NEET 2017 · Closed and open pipes
Given: two neighbouring harmonics at 220 Hz and 260 Hz of a pipe closed at one end.
Idea: a closed pipe sounds only the odd harmonics f₀,3f₀,5f₀,…, so two neighbours differ by 2f₀.
260-220=40 Hz.
2f₀=40.
f₀=20 Hz.
(Checking: the odd multiples of 20 Hz include 220 Hz as the 11th harmonic and 260 Hz as the 13th.)
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