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Asked in NEET 2023 · Closed and open pipes
Idea: the boundary conditions fix how much of a wavelength fits in each pipe.
An open pipe has antinodes at both ends, so its fundamental fits half a wavelength: fₒ=v/(2ℓ).
A closed pipe has a node at the closed end and an antinode at the open one, so its fundamental fits a quarter wavelength: f_c=v/(4ℓ).
(fₒ)/(f_c)=v/(2ℓ)×(4ℓ)/v.
(fₒ)/(f_c)=2:1.
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