Two slits in Young's double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is 600×10⁻⁹ m then the fringe separation is

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(4) 4×10⁻⁴ m. Given: d=1.5 mm =1.5×10⁻³ m, D=1 m, λ=600×10⁻⁹ m =6×10⁻⁷ m. Idea: successive bright fringes in Young's experiment are evenly spaced, by the fringe width β=(λ D)/d. β=(6×10⁻⁷×1)/(1.5×10⁻³). 6/(1.5)=4 and (10⁻⁷)/(10⁻³)=10⁻⁴. β=4×10⁻⁴ m, that is 0.4 mm.

Two slits in Young's double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is 600×10⁻⁹ m then the fringe separation is

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