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Asked in CBSE AIPMT 2014 · Single slit diffraction
Given: λ=600 nm, a=1 mm, D=2 m.
Idea: the two first dark fringes sit symmetrically about the centre, so the distance between them is twice the half-width.
Half-width =(λ D)/a=(600×10⁻⁹×2)/(10⁻³)=1.2×10⁻³ m.
Distance between them =2×1.2×10⁻³.
=2.4×10⁻³ m.
=2.4 mm.
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