A mass of 0.5 kg moving with a speed of 1.5 m s⁻¹ on a horizontal smooth surface, collides with a nearly weightless spring of force constant k=50 N m⁻¹. The maximum compression of the spring would be

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(1) 0.15 m. Given: m=0.5 kg, v=1.5 m s⁻¹, k=50 N m⁻¹, and the surface is smooth. Idea: at maximum compression the block has stopped, so its kinetic energy has all gone into the spring. 1/2mv²=1/2kx², so x=v√m/k. x²=(mv²)/k=(0.5×(1.5)²)/(50)=(1.125)/(50)=0.0225. x=0.15 m.

A mass of 0.5 kg moving with a speed of 1.5 m s⁻¹ on a horizontal smooth surface, collides with a nearly weightless spring of force constant k=50 N m⁻¹. The maximum compression of the spring would be

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