Practice portal › Work, Energy and Power › Power
Asked in NEET 2016 Phase-I · Average and instantaneous power
Given: m=1 kg starting from rest, ⃗F=2tı̂+3t²ȷ̂ N.
Idea: the force varies, so the velocity has to be built up by integrating the acceleration before the power can be found.
⃗a=(⃗F)/m=2tı̂+3t²ȷ̂.
⃗v=∫⃗a dt=t²ı̂+t³ȷ̂ (starting from rest, so no constant).
P=⃗F·⃗v=(2t)(t²)+(3t²)(t³).
P=(2t³+3t⁵) W.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer