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A body of mass 1 kg begins to move under the action of time dependent force ⃗F=(2tı̂+3t²ȷ̂) N, where ı̂ and ȷ̂ are unit vectors along x and y axis. What power will be developed by the force at the time t?

Asked in NEET 2016 Phase-I · Average and instantaneous power

Answer: (2) (2t³+3t⁵) W

Step-by-step solution

Given: m=1 kg starting from rest, ⃗F=2tı̂+3t²ȷ̂ N.

Idea: the force varies, so the velocity has to be built up by integrating the acceleration before the power can be found.

⃗a=(⃗F)/m=2tı̂+3t²ȷ̂.

⃗v=∫⃗a dt=t²ı̂+t³ȷ̂ (starting from rest, so no constant).

P=⃗F·⃗v=(2t)(t²)+(3t²)(t³).

P=(2t³+3t⁵) W.

Why the other options are wrong

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