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Asked in NEET 2018 · Energy in vertical circular motion
Given: the body starts from rest at height h and just completes a vertical loop of diameter D, so radius R=D/2.
Idea: a loop is only just completed when the speed at the bottom is √5gR — the least speed that still leaves √gR at the top.
Speed at the bottom of the loop, from the slide: v=√2gh.
Condition: √2gh=√5gR=√(5gD)/2.
2gh=(5gD)/2.
h=(5D)/4.
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