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Asked in NEET 2018 · Coefficient of restitution and rebound
Given: m at speed v strikes 4m at rest; the lighter block stops dead.
Idea: momentum fixes the heavy block's speed, and the coefficient of restitution then compares separation with approach.
mv+0=m(0)+4mv', so v'=v/4.
Velocity of approach =v-0=v.
Velocity of separation =v'-0=v/4.
e=(v/4)/v=0.25.
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