Practice portal › Units and Measurements › Deriving Relations by Dimensional Analysis
Asked in NEET-II 2016 · Deriving a relation by dimensional analysis
[h]=[ML²T⁻¹], [G]=[M⁻¹L³T⁻²], [c]=[LT⁻¹]
Idea: multiplying h by G cancels the mass, which is what a pure length needs.
[hG]=[ML²T⁻¹][M⁻¹L³T⁻²]=[L⁵T⁻³]
[√hG]=[L^5/2T^-3/2]
[c^3/2]=[L^3/2T^-3/2]
([L^5/2T^-3/2])/([L^3/2T^-3/2])=[L]
This combination is the Planck length.
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