Practice portal › Units and Measurements › Errors in the Simple Pendulum Experiment

The percentage error in the measurement of g is, given that g=(4π²L)/(T²), L=(10±0.1) cm and T=(100±1) s:

Asked in Re-NEET 2022 · Error in g from a pendulum experiment

Answer: (4) 3%

Step-by-step solution

Given: g=(4π²L)/(T²), L=(10±0.1) cm, T=(100±1) s.

(Δ L)/L×100=(0.1)/(10)×100=1%

(Δ T)/T×100=1/(100)×100=1%

Idea: 4π² is exact, so only L and T carry error, and T appears squared.

(Δ g)/g×100=(Δ L)/L×100+2×(Δ T)/T×100=1+2(1)

=3%

Why the other options are wrong

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer