Each side of a metallic cube of mass 5.580 kg is measured to be 9.0 cm. Keeping the significant figures in view, the density of the material of the cube can be best expressed as X× 10³ kg m⁻³, where the value of X is:

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Accepted Answer

(4) 7.7. Given: m=5.580 kg, side a=9.0 cm=9.0×10⁻² m. V=a³=(9.0×10⁻²)³=7.29×10⁻⁴ m³ ρ=m/V=(5.580)/(7.29×10⁻⁴)=7654.3 kg m⁻³ Idea: the answer carries as many significant figures as the least precise measurement. 9.0 cm has two significant figures, so ρ=7.7×10³ kg m⁻³. Hence X=7.7.

Each side of a metallic cube of mass 5.580 kg is measured to be 9.0 cm. Keeping the significant figures in view, the density of the material of the cube can be best expressed as X× 10³ kg m⁻³, where the value of X is:

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