Practice portal › Thermal Properties of Matter › Linear, Areal and Volume Expansion
Asked in NEET 2019 · Linear expansion and composite rods
Given: l_Cu=88 cm, α_Cu=1.7×10⁻⁵ K⁻¹, α_Al=2.2×10⁻⁵ K⁻¹.
Idea: the difference in length is fixed at every temperature only if the two rods lengthen by exactly the same amount, so Δ l_Cu=Δ l_Al.
l_Cuα_CuΔ T=l_Alα_AlΔ T
l_Al=(l_Cuα_Cu)/(α_Al)=(88×1.7×10⁻⁵)/(2.2×10⁻⁵)
l_Al=(149.6)/(2.2)=68 cm
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer