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One mole of an ideal monatomic gas undergoes a cyclic process as shown in the figure. The total heat supplied to the gas is :

Asked in Re-NEET 2026 · Work as the Area of a Closed Loop

Figure: Work as the Area of a Closed Loop
Answer: (3) 600 J

Step-by-step solution

Over a complete cycle Δ U=0, so the net heat supplied equals the net work done by the gas.

The cycle a→ b→ c→ d→ a runs clockwise on the P-V diagram, so the work is positive and equals the enclosed area.

W=(300-100)×(5-2)=600 J, so Q=600 J.

Why the other options are wrong

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