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The efficiency of a Carnot engine operating with reservoir temperature of 100°C and -23°C will be

Asked in NEET 1997 · Entropy and the Carnot Engine

Answer: (2) (373-250)/(373)

Step-by-step solution

Idea: η=(T₁-T₂)/(T₁), with both temperatures absolute.

T₁=100°C=100+273=373 K.

T₂=-23°C=-23+273=250 K.

η=(373-250)/(373).

(That is (123)/(373)=33%.)

Why the other options are wrong

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