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An ideal gas follows a process described by the equation PV²=C from the initial (P₁,V₁,T₁) to the final (P₂,V₂,T₂) thermodynamic states, where C is a constant. Then:

Asked in NEET Re-2022 · Ideal Gas Equation and Mixtures

Answer: (4) If V₂>V₁ then T₂<T₁

Step-by-step solution

Given: the process obeys PV²=C with C constant.

Idea: eliminate P between the process equation and the ideal gas law to get a relation in T and V alone.

PV=nRT gives P=(nRT)/V.

Substituting: (nRT)/V· V²=C, so nRTV=C.

Hence TV= constant: temperature and volume are inversely related along this process.

So if V₂>V₁ then T₂<T₁.

Why the other options are wrong

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