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A screw gauge has a least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is:

Asked in NEET 2020 · Pitch and least count

Answer: (2) 0.5 mm

Step-by-step solution

Given: L.C.=0.01 mm and 50 circular divisions.

Idea: the least count is the distance the screw advances for one division of the circular scale, so the pitch is that distance times the number of divisions.

L.C.=(pitch)/(number of divisions)

pitch=L.C.×50=0.01×50

pitch=0.5 mm

Why the other options are wrong

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