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Asked in CBSE AIPMT 2000 · Transistor currents and current gain
Idea: start from the current split at the emitter, I_E=I_B+I_C.
α=(I_C)/(I_E) and β=(I_C)/(I_B).
So β=(I_C)/(I_E-I_C), and dividing top and bottom by I_E gives β=(I_C/I_E)/(1-I_C/I_E).
β=α/(1-α).
As a check, α=0.98 gives β=49, which is the usual order of magnitude.
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