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An n-p-n transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Ω is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 Ω, the voltage gain and the power gain of the amplifier will respectively be

Asked in NEET 2016 (Phase I) · Amplifier gain and phase

• (1) 4, 4
• (2) 4, 3.69
• (3) 4, 3.84
• (4) 3.69, 3.84

Step-by-step solution

Why the other options are wrong

• (1) comes from the voltage gain is right, but repeating it as the power gain skips the current-gain factor: Aₚ=0.96×4=3.84, not 4.
• (2) comes from the voltage gain is right, but 3.69 applies the 0.96 once too often: 0.96×3.84=3.69. The power gain needs the current gain used once, not twice.
• (4) comes from the power gain is right, but 3.69 as a voltage gain is 0.96×0.96×(800)/(192), the current gain counted twice over; using it once gives 4.

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