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Asked in NEET 2025 · Gate combinations and truth tables
Idea: write each gate's output in Boolean form and multiply them out.
The upper gate gives Y₁=A+B and the lower one Y₂=A· B.
The final AND gives Y=Y₁· Y₂=A+B·A· B.
A+B is 1 only when A=B=0, and in that case A· B is 1 as well, so the second factor never removes anything the first kept.
Y=A+B, which is a NOR gate.
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