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Asked in Re-NEET 2026 · Combinations and silvered lenses
L₁: u=-30 cm, f=+10 cm. 1/v=1/f+1/u=1/(10)-1/(30)=1/(15), so v=15 cm.
That image lies 15-3=12 cm beyond L₂: a virtual object for L₂, u=+12 cm.
L₂: 1/v=-1/(10)+1/(12)=-1/(60), so v=-60 cm.
The final image is 60 cm to the left of the concave lens.
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