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Light enters at an angle of incidence in a transparent rod of refractive index μ. For what value of the refractive index of the material of the rod the light once entered into it will not leave it through its lateral face whatsoever be the value of angle of incidence?

Asked in CBSE AIPMT 1998 · Total internal reflection and optical fibres

Answer: (1) μ>√2

Step-by-step solution

Given: light enters the flat end of a rod of index μ at some angle i, and must not escape through the curved side whatever i is.

Idea: the refracted ray makes r with the rod's axis, so it strikes the lateral face at 90°-r; that angle has to exceed the critical angle for every possible r.

sin(90°-r)>sin C, that is cos r>1/μ.

The hardest case is grazing entry, i=90°, which gives the largest r: sin r=1/μ.

cos r=√1-1/(μ²)>1/μ

1-1/(μ²)>1/(μ²), so μ²>2

μ>√2

Why the other options are wrong

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