Practice portal › Rotational Motion › Moment of Inertia
Asked in NEET 2026 · Standard bodies and axis theorems
Mass of the ring: M=mL; radius: 2π r=L, so r=L/(2π).
The axis yy' lies in the plane of the ring and touches it, so it is parallel to a diameter at distance r.
I_yy'=(Mr²)/2+Mr²=3/2Mr².
I_yy'=3/2 mL (L²)/(4π²)=(3mL³)/(8π²).
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