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A thin wire of length 'L' and linear mass density 'm' is bent into a circular ring (in x-y plane) with centre 'C' as shown in figure. The moment of inertia of the ring about an axis yy' will be :

Asked in NEET 2026 · Standard bodies and axis theorems

Figure: Standard bodies and axis theorems
Answer: (4) (3mL³)/(8π²)

Step-by-step solution

Mass of the ring: M=mL; radius: 2π r=L, so r=L/(2π).

The axis yy' lies in the plane of the ring and touches it, so it is parallel to a diameter at distance r.

I_yy'=(Mr²)/2+Mr²=3/2Mr².

I_yy'=3/2 mL (L²)/(4π²)=(3mL³)/(8π²).

Why the other options are wrong

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