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Asked in NEET 2023 · Radius of gyration and numericals
Given: solid sphere and thin hollow sphere, same M and R, each about a diameter.
Idea: the radius of gyration is defined by I=Mk², so k=√I/M.
Solid sphere: I=2/5MR², so k₁=R√2/5.
Thin hollow sphere: I=2/3MR², so k₂=R√2/3.
(k₁)/(k₂)=√(2/5)/(2/3)=√3/5=√3:√5≈0.775.
That is neither 5:3, nor 2:5, nor 5:2, so none of the listed ratios is correct.
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