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The angular speed of a flywheel is increased from 600 rpm to 1200 rpm in 10 s. The number of revolutions completed by the flywheel during this time is:

Asked in NEET 2026 · Equations of rotational motion

Answer: (3) 150

Step-by-step solution

Given: N₁=600 rpm, N₂=1200 rpm, t=10 s.

Idea: the angular acceleration is uniform, so the mean angular speed is the arithmetic mean of the two end values.

N=(600+1200)/2=900 rpm=(900)/(60)=15 rev s⁻¹

Revolutions =N t=15×10=150.

Why the other options are wrong

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