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Asked in NEET 2026 · Equations of rotational motion
Given: N₁=600 rpm, N₂=1200 rpm, t=10 s.
Idea: the angular acceleration is uniform, so the mean angular speed is the arithmetic mean of the two end values.
N=(600+1200)/2=900 rpm=(900)/(60)=15 rev s⁻¹
Revolutions =N t=15×10=150.
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