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Asked in NEET 2018 · Rolling kinematics and energy
Given: a solid sphere rolling without slipping, I=2/5mR², v=ω R.
Kₜ=1/2mv²
Kᵣ=1/2(2/5mR²)(v²)/(R²)=1/5mv²
Idea: add them to get the total, then form the ratio.
Kₜ+Kᵣ=1/2mv²+1/5mv²=7/(10)mv²
(Kₜ)/(Kₜ+Kᵣ)=(1/2)/(7/10)=(10)/(14)=5/7
The ratio is 5:7.
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