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A solid sphere is in rolling motion. In rolling motion a body possesses translational kinetic energy (Kₜ) as well as rotational kinetic energy (Kᵣ) simultaneously. The ratio Kₜ:(Kₜ+Kᵣ) for the sphere is

Asked in NEET 2018 · Rolling kinematics and energy

Answer: (2) 5 : 7

Step-by-step solution

Given: a solid sphere rolling without slipping, I=2/5mR², v=ω R.

Kₜ=1/2mv²

Kᵣ=1/2(2/5mR²)(v²)/(R²)=1/5mv²

Idea: add them to get the total, then form the ratio.

Kₜ+Kᵣ=1/2mv²+1/5mv²=7/(10)mv²

(Kₜ)/(Kₜ+Kᵣ)=(1/2)/(7/10)=(10)/(14)=5/7

The ratio is 5:7.

Why the other options are wrong

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