Practice portal › Rotational Motion › Rotational Dynamics
Asked in NEET-II 2016 · Rotational energy and released bodies
Given: K_A=K_B and I_B>I_A.
Idea: write the kinetic energy in terms of angular momentum, so the comparison turns on I alone.
K=1/2Iω² and L=Iω, so K=(L²)/(2I).
L=√2IK
With K the same for both, L increases with I.
I_B>I_A⇒ L_B>L_A. The masses play no part, since I is given directly.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer