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Asked in NEET 2017 · Conservation of angular momentum
Given: two discs, each of moment of inertia I, spinning at ω₁ and ω₂ about the same axis, then brought into contact.
Idea: the friction between the faces is internal, so angular momentum is conserved while kinetic energy is not.
Iω₁+Iω₂=2Iω_f⇒ω_f=(ω₁+ω₂)/2
Eᵢ=1/2Iω₁²+1/2Iω₂²=I/2(ω₁²+ω₂²)
E_f=1/2(2I)ω_f²=(I(ω₁+ω₂)²)/4
Δ E=I/4[2(ω₁²+ω₂²)-(ω₁+ω₂)²]
Δ E=1/4I(ω₁-ω₂)²
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