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Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc has angular velocities ω₁ and ω₂. They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is

Asked in NEET 2017 · Conservation of angular momentum

Answer: (1) 1/4I(ω₁-ω₂)²

Step-by-step solution

Given: two discs, each of moment of inertia I, spinning at ω₁ and ω₂ about the same axis, then brought into contact.

Idea: the friction between the faces is internal, so angular momentum is conserved while kinetic energy is not.

Iω₁+Iω₂=2Iω_f⇒ω_f=(ω₁+ω₂)/2

Eᵢ=1/2Iω₁²+1/2Iω₂²=I/2(ω₁²+ω₂²)

E_f=1/2(2I)ω_f²=(I(ω₁+ω₂)²)/4

Δ E=I/4[2(ω₁²+ω₂²)-(ω₁+ω₂)²]

Δ E=1/4I(ω₁-ω₂)²

Why the other options are wrong

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