Practice portal › Rotational Motion › Rotational Dynamics
Asked in NEET 2018 · Rotational energy and released bodies
Given: solid sphere, disk and ring, all of mass M and radius R, all spinning at ω about their symmetry axes.
Idea: the work needed to stop a body equals its kinetic energy, W=1/2Iω², and M, R and ω are the same for all three — so only I separates them.
I_A=2/5MR²=0.4MR²
I_B=1/2MR²=0.5MR²
I_C=MR²
I_C>I_B>I_A, so W_C>W_B>W_A.
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