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A body is executing simple harmonic motion. When the displacements from the mean position are 4 cm and 5 cm, the corresponding velocities of the body are 10 cm s⁻¹ and 8 cm s⁻¹. Then the time period of the body is

Asked in CBSE AIPMT 1991 · v-x and a-x relations

Answer: (3) π s

Step-by-step solution

Given: v=10 cm s⁻¹ at x=4 cm, and v=8 cm s⁻¹ at x=5 cm.

Idea: write v²=ω²(A²-x²) twice and subtract, so the unknown amplitude cancels.

100=ω²(A²-16)

64=ω²(A²-25)

36=ω²(25-16)=9ω²

ω=2 rad s⁻¹

T=(2π)/2=π s

Why the other options are wrong

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