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A body of mass m is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass. When the mass m is slightly pulled down and released, it oscillates with a time period of 3 s. When the mass m is increased by 1 kg, the time period of oscillations becomes 5 s. The value of m in kg is

Asked in NEET-II 2016 · Mass added or removed

Answer: (4) 9/(16)

Step-by-step solution

Given: T₁=3 s with mass m, and T₂=5 s with mass m+1.

Idea: for a spring T=2π√m/k, so T²∝ m and the unknown k cancels in the ratio.

(T₂²)/(T₁²)=(m+1)/m

(25)/9=(m+1)/m

25m=9m+9

16m=9, so m=9/(16) kg

Why the other options are wrong

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