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The displacement of a particle executing simple harmonic motion is given by y=A₀+A sin ω t+B cos ω t. Then the amplitude of its oscillation is given by

Asked in NEET 2019 · Resultant amplitude and phase

Answer: (3) √A²+B²

Step-by-step solution

Given: y=A₀+A sin ω t+B cos ω t.

Idea: a constant shifts the centre of the motion; only the two sinusoids set the amplitude.

Write A sin ω t+B cos ω t=R sin(ω t+φ).

Expanding, R cos φ=A and R sin φ=B.

R²=A²+B²

y=A₀+R sin(ω t+φ), so the particle swings by ± R about y=A₀.

Amplitude =√A²+B²

Why the other options are wrong

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