Practice portal › Oscillations › Superposition of Two SHMs
Asked in NEET 2019 · Resultant amplitude and phase
Given: y=A₀+A sin ω t+B cos ω t.
Idea: a constant shifts the centre of the motion; only the two sinusoids set the amplitude.
Write A sin ω t+B cos ω t=R sin(ω t+φ).
Expanding, R cos φ=A and R sin φ=B.
R²=A²+B²
y=A₀+R sin(ω t+φ), so the particle swings by ± R about y=A₀.
Amplitude =√A²+B²
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