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A body is executing simple harmonic motion with frequency n. The frequency of its potential energy is

Asked in NEET 2021 · Kinetic, potential and total energy

Answer: (2) 2n

Step-by-step solution

Given: displacement x=A sin ω t with frequency n=ω/(2π).

Idea: the potential energy depends on x², and squaring a sinusoid doubles its frequency.

U=1/2 kx²=1/2 kA² sin²ω t

sin²ω t=(1-cos 2ω t)/2

The only time-varying term has angular frequency 2ω, so the frequency of U is 2n.

Why the other options are wrong

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