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If x=5 sin (π t+π/3) m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are

Asked in NEET 2024 · Displacement equation and phase

Answer: (2) 5 m, 2 s

Step-by-step solution

Given: x=5 sin (π t+π/3) m.

Idea: compare with the standard form x=A sin(ω t+φ).

Amplitude A=5 m (the equation is written in metres).

ω=π rad s⁻¹

T=(2π)/ω=(2π)/π=2 s

Why the other options are wrong

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