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An unknown nucleus has a nuclear density of 2.29×10¹⁷ kg/m³ and mass of 19.926×10⁻²⁷ kg. Its mass number A is approximately: (Take R₀=1.2×10⁻¹⁵ m, 4π=12.56)

Asked in NEET 2026 · Nuclear radius and density

Answer: (1) 12

Step-by-step solution

Volume =(mass)/(density) and V=4/3π R³=4/3π R₀³A.

A=(3M)/(4πρ R₀³)=(3×19.926×10⁻²⁷)/(2.29×10¹⁷×12.56×(1.2×10⁻¹⁵)³).

Denominator: 2.29×10¹⁷×12.56×1.728×10⁻⁴⁵=4.97×10⁻²⁷.

A=(5.978×10⁻²⁶)/(4.97×10⁻²⁷)=12.0.

Why the other options are wrong

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