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A certain mass of hydrogen is changed to helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per nucleon is (given 1 u=931 MeV)

Asked in NEET 2013 · Energy released in fission and fusion

Answer: (3) 6.675 MeV

Step-by-step solution

First find the total energy released from the mass defect.

E=Δ m×931=0.02866×931=26.7 MeV.

Four hydrogen nuclei fuse into one helium nucleus, which holds 4 nucleons.

The energy liberated per nucleon is that total shared over those 4 nucleons.

E/A=(26.7)/4=6.675 MeV per nucleon.

Why the other options are wrong

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