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Asked in CBSE AIPMT 2000 · Q-value, decay and conservation laws
Balance the mass number: 11=11+0+A_X, so X has mass number 0.
Balance the charge: 6=5+1+Z_X, so X carries no charge.
X is therefore neutral with mass number 0, which among the options narrows it to a neutrino or an antineutrino.
Lepton bookkeeping settles which: positron emission creates an antiparticle of the electron, so it must be paired with a neutrino.
X is a neutrino.
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